view mod_roster_allinall/mod_roster_allinall.lua @ 5407:149634647b48

mod_http_oauth2: Don't issue client_secret when not using authentication This is pretty much only for implicit flow, which is considered insecure anyway, so this is of limited value. If we delete all the implicit flow code, this could be reverted.
author Kim Alvefur <zash@zash.se>
date Tue, 02 May 2023 16:39:32 +0200
parents 3ae8c81a348b
children
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local rostermanager = require"core.rostermanager";
local jid_join = require"util.jid".join;
local host = module.host;
local sessions = prosody.hosts[host].sessions;

-- Make a *one-way* subscription. User will see when contact is online,
-- contact will not see when user is online.
local function subscribe(user, contact)
	local user_jid, contact_jid = jid_join(user, host), jid_join(contact, host);

	-- Update user's roster to say subscription request is pending...
	rostermanager.set_contact_pending_out(user, host, contact_jid);
	-- Update contact's roster to say subscription request is pending...
	rostermanager.set_contact_pending_in(contact, host, user_jid);
	-- Update contact's roster to say subscription request approved...
	rostermanager.subscribed(contact, host, user_jid);
	-- Update user's roster to say subscription request approved...
	rostermanager.process_inbound_subscription_approval(user, host, contact_jid);

	-- Push updates to both rosters
	rostermanager.roster_push(user, host, contact_jid);
	rostermanager.roster_push(contact, host, user_jid);
end


module:hook("resource-bind", function(event)
	local session = event.session;
	local user = session.username;
	local user_jid = jid_join(user, host);
	for contact in pairs(sessions) do
		if contact ~= user then
			local contact_jid = jid_join(contact, host);
			if not rostermanager.is_contact_subscribed(user, host, contact_jid) then
				subscribe(contact, user);
			end
			if not rostermanager.is_contact_subscribed(contact, host, user_jid) then
				subscribe(user, contact);
			end
		end
	end
end);