Mercurial > prosody-modules
view mod_roster_allinall/mod_roster_allinall.lua @ 5407:149634647b48
mod_http_oauth2: Don't issue client_secret when not using authentication
This is pretty much only for implicit flow, which is considered insecure
anyway, so this is of limited value. If we delete all the implicit flow
code, this could be reverted.
author | Kim Alvefur <zash@zash.se> |
---|---|
date | Tue, 02 May 2023 16:39:32 +0200 |
parents | 3ae8c81a348b |
children |
line wrap: on
line source
local rostermanager = require"core.rostermanager"; local jid_join = require"util.jid".join; local host = module.host; local sessions = prosody.hosts[host].sessions; -- Make a *one-way* subscription. User will see when contact is online, -- contact will not see when user is online. local function subscribe(user, contact) local user_jid, contact_jid = jid_join(user, host), jid_join(contact, host); -- Update user's roster to say subscription request is pending... rostermanager.set_contact_pending_out(user, host, contact_jid); -- Update contact's roster to say subscription request is pending... rostermanager.set_contact_pending_in(contact, host, user_jid); -- Update contact's roster to say subscription request approved... rostermanager.subscribed(contact, host, user_jid); -- Update user's roster to say subscription request approved... rostermanager.process_inbound_subscription_approval(user, host, contact_jid); -- Push updates to both rosters rostermanager.roster_push(user, host, contact_jid); rostermanager.roster_push(contact, host, user_jid); end module:hook("resource-bind", function(event) local session = event.session; local user = session.username; local user_jid = jid_join(user, host); for contact in pairs(sessions) do if contact ~= user then local contact_jid = jid_join(contact, host); if not rostermanager.is_contact_subscribed(user, host, contact_jid) then subscribe(contact, user); end if not rostermanager.is_contact_subscribed(contact, host, user_jid) then subscribe(user, contact); end end end end);