view mod_roster_allinall/mod_roster_allinall.lua @ 5608:1893ae742f66

mod_http_oauth2: Show errors on device flow user code entry page If the user enters the code incorrectly, having to click back to try again is no fun. Instead, show the error and the code entry form again.
author Kim Alvefur <zash@zash.se>
date Wed, 19 Jul 2023 13:05:47 +0200
parents 3ae8c81a348b
children
line wrap: on
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local rostermanager = require"core.rostermanager";
local jid_join = require"util.jid".join;
local host = module.host;
local sessions = prosody.hosts[host].sessions;

-- Make a *one-way* subscription. User will see when contact is online,
-- contact will not see when user is online.
local function subscribe(user, contact)
	local user_jid, contact_jid = jid_join(user, host), jid_join(contact, host);

	-- Update user's roster to say subscription request is pending...
	rostermanager.set_contact_pending_out(user, host, contact_jid);
	-- Update contact's roster to say subscription request is pending...
	rostermanager.set_contact_pending_in(contact, host, user_jid);
	-- Update contact's roster to say subscription request approved...
	rostermanager.subscribed(contact, host, user_jid);
	-- Update user's roster to say subscription request approved...
	rostermanager.process_inbound_subscription_approval(user, host, contact_jid);

	-- Push updates to both rosters
	rostermanager.roster_push(user, host, contact_jid);
	rostermanager.roster_push(contact, host, user_jid);
end


module:hook("resource-bind", function(event)
	local session = event.session;
	local user = session.username;
	local user_jid = jid_join(user, host);
	for contact in pairs(sessions) do
		if contact ~= user then
			local contact_jid = jid_join(contact, host);
			if not rostermanager.is_contact_subscribed(user, host, contact_jid) then
				subscribe(contact, user);
			end
			if not rostermanager.is_contact_subscribed(contact, host, user_jid) then
				subscribe(user, contact);
			end
		end
	end
end);