view mod_http_user_count/mod_http_user_count.lua @ 4651:8231774f5bfd

mod_cloud_notify_encrypted: Ensure body substring remains valid UTF-8 The `body:sub()` call risks splitting the string in the middle of a multi-byte UTF-8 sequence. This should have been caught by util.stanza validation, but that would have caused some havoc, at the very least causing the notification to not be sent. There have been no reports of this happening. Likely because this module isn't widely deployed among users with languages that use many longer UTF-8 sequences. The util.encodings.utf8.valid() function is O(n) where only the last sequence really needs to be checked, but it's in C and expected to be fast.
author Kim Alvefur <zash@zash.se>
date Sun, 22 Aug 2021 13:22:59 +0200
parents a45f2f79e99b
children
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local it = require "util.iterators";
local jid_split = require "util.jid".prepped_split;

module:depends("http");

local function check_muc(jid)
	local room_name, host = jid_split(jid);
	if not hosts[host] then
		return nil, "No such host: "..host;
	elseif not hosts[host].modules.muc then
		return nil, "Host '"..host.."' is not a MUC service";
	end
	return room_name, host;
end

module:provides("http", {
    route = {
        ["GET /sessions"] = function () return tostring(it.count(it.keys(prosody.full_sessions))); end;
        ["GET /users"] = function () return tostring(it.count(it.keys(prosody.bare_sessions))); end;
        ["GET /host"] = function () return tostring(it.count(it.keys(prosody.hosts[module.host].sessions))); end;
        ["GET /room/*"] = function (request, room_jid)
        	local name, host = check_muc(room_jid);
        	if not name then
        		return "0";
        	end
       		local room = prosody.hosts[host].modules.muc.rooms[name.."@"..host];
       		if not room then
       			return "0";
       		end
        	return tostring(it.count(it.keys(room._occupants)));
        end;
    };
});