view mod_roster_allinall/mod_roster_allinall.lua @ 5186:fa3059e653fa

mod_http_oauth2: Implement the Implicit flow Everyone says this is insecure and bad, but it's also the only thing that makes sense for e.g. pure JavaScript clients, but hey implement this even more complicated thing instead!
author Kim Alvefur <zash@zash.se>
date Thu, 02 Mar 2023 22:06:50 +0100
parents 3ae8c81a348b
children
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local rostermanager = require"core.rostermanager";
local jid_join = require"util.jid".join;
local host = module.host;
local sessions = prosody.hosts[host].sessions;

-- Make a *one-way* subscription. User will see when contact is online,
-- contact will not see when user is online.
local function subscribe(user, contact)
	local user_jid, contact_jid = jid_join(user, host), jid_join(contact, host);

	-- Update user's roster to say subscription request is pending...
	rostermanager.set_contact_pending_out(user, host, contact_jid);
	-- Update contact's roster to say subscription request is pending...
	rostermanager.set_contact_pending_in(contact, host, user_jid);
	-- Update contact's roster to say subscription request approved...
	rostermanager.subscribed(contact, host, user_jid);
	-- Update user's roster to say subscription request approved...
	rostermanager.process_inbound_subscription_approval(user, host, contact_jid);

	-- Push updates to both rosters
	rostermanager.roster_push(user, host, contact_jid);
	rostermanager.roster_push(contact, host, user_jid);
end


module:hook("resource-bind", function(event)
	local session = event.session;
	local user = session.username;
	local user_jid = jid_join(user, host);
	for contact in pairs(sessions) do
		if contact ~= user then
			local contact_jid = jid_join(contact, host);
			if not rostermanager.is_contact_subscribed(user, host, contact_jid) then
				subscribe(contact, user);
			end
			if not rostermanager.is_contact_subscribed(contact, host, user_jid) then
				subscribe(user, contact);
			end
		end
	end
end);