Mercurial > prosody-modules
view mod_roster_allinall/mod_roster_allinall.lua @ 5186:fa3059e653fa
mod_http_oauth2: Implement the Implicit flow
Everyone says this is insecure and bad, but it's also the only thing
that makes sense for e.g. pure JavaScript clients, but hey implement
this even more complicated thing instead!
author | Kim Alvefur <zash@zash.se> |
---|---|
date | Thu, 02 Mar 2023 22:06:50 +0100 |
parents | 3ae8c81a348b |
children |
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local rostermanager = require"core.rostermanager"; local jid_join = require"util.jid".join; local host = module.host; local sessions = prosody.hosts[host].sessions; -- Make a *one-way* subscription. User will see when contact is online, -- contact will not see when user is online. local function subscribe(user, contact) local user_jid, contact_jid = jid_join(user, host), jid_join(contact, host); -- Update user's roster to say subscription request is pending... rostermanager.set_contact_pending_out(user, host, contact_jid); -- Update contact's roster to say subscription request is pending... rostermanager.set_contact_pending_in(contact, host, user_jid); -- Update contact's roster to say subscription request approved... rostermanager.subscribed(contact, host, user_jid); -- Update user's roster to say subscription request approved... rostermanager.process_inbound_subscription_approval(user, host, contact_jid); -- Push updates to both rosters rostermanager.roster_push(user, host, contact_jid); rostermanager.roster_push(contact, host, user_jid); end module:hook("resource-bind", function(event) local session = event.session; local user = session.username; local user_jid = jid_join(user, host); for contact in pairs(sessions) do if contact ~= user then local contact_jid = jid_join(contact, host); if not rostermanager.is_contact_subscribed(user, host, contact_jid) then subscribe(contact, user); end if not rostermanager.is_contact_subscribed(contact, host, user_jid) then subscribe(user, contact); end end end end);